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gunnatvinson
26.06.2019 •
Chemistry
The gas stream from a reactor contains 25 mol% ammonia and the rest inert gases. the total flow is 181 kg mol/hr to an absorption column at 303 k and 1 x 105 pa total pressure. water containing .005 mol fraction is the solvent. the outlet gas concentration of ammonia must be ≤ 2 mol% ammonia. what is the minimum water flow rate to accomplish this separation? using 1.5 times this minimum ratio plot the equilibrium and operating lines (not dilute! )
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Ответ:
Molarity = 0.014 M
Explanation:
Given data:
Volume of H₂SO₄ = 24.9 mL
Molarity of H₂SO₄ = ?
Volume of LiOH = 20.5 mL
Molarity of LiOH = 0.0365 M
Solution:
Volume of LiOH:
20.5 mL × 1 L /1000 mL
0.0205L
Volume of H₂SO₄:
24.9 mL × 1 L /1000 mL
0.0249 L
Chemical equation:
H₂SO₄ + 2LiOH → Li₂SO₄ + 2H₂O
Number of moles of LiOH:
Molarity = number of moles / volume in L
0.0365 M = number of moles / 0.0205L
n = 0.0365 M × 0.0205L
n = 0.0365 mol/L × 0.0205L
n = 0.0007 mol
now we will compare the moles of LiOH and H₂SO₄
LiOH : H₂SO₄
2 : 1
0.0007 : 1/2×0.0007 = 0.00035 mol
Molarity of H₂SO₄:
Molarity = number of moles / volume in L
Molarity = 0.00035 mol / 0.0249 L
Molarity = 0.014 M