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25.10.2020 •
Chemistry
The half-life of polonium-218 s 3.0 min. If you start with 16 mg of polonium-218, how much time must pass for only 1.0 mg to remain?
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Ответ:
Fraction remaining = 0.5n where n = # of half lives elapsed
Fraction remaining = 2.0 g/30.0 g = 0.06667
0.06667 = 0.5n
log 0.06667 = n log 0.5
n = 3.907 half lives
3.907 half lives x 3.0 min/half life = 11.7 minutes
Explanation:
Ответ: