The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way:
OCl−+I−→OI−+Cl−.
This rapid reaction gives the following rate data:
[OCl−](M) [I]−(M) Rate (M/s)
1.5×10^−3 1.5×10^−3 1.36×10^−4
3.0×10^−3 1.5×10^−3 2.72×10^−4
1.5×10^−3 3.0×10^−3 2.72×10^−4
a. Write the rate law for this reaction.
b. Calculate the rate constant with proper units.
c. Calculate the rate when [OCl-]= 1.8×10^3 M and [I-]= 6.0×10^4 M .
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Ответ:
a) The rate law for this reaction:
b)The rate constant of the reaction is .
c)The rate of the reaction at given concentration will be .
Explanation:
a) Rate law of the reaction is given by :
1) Rate of the reaction when and .
..[1]
2) Rate of the reaction when and .
..[2]
3) Rate of the reaction when and .
..[3]
[1] ÷ [2]
On solving the equation we get value of x :
x = 1
[1] ÷ [3]
On solving the equation we get value of y :
y = 1
The rate law for this reaction:
b)
Rate of the reaction when and .
The rate constant of the reaction is .
c)
Let the rate of the reaction when and be R.
The rate of the reaction at given concentration will be .
Ответ:
20pcs I hope it help or maybe 30