The mass ratio of sodium to fluorine in sodium fluoride is 1.21: 1. a sample of sodium fluoride produced 32.5 \({\rm g}\) of sodium upon decomposition. how much fluorine (in grams) was formed? .

Let us assume the common ratio to be = x
Then
1.21x + x = 32.5
2.21x = 32.5
x = 32.5/2.21
   = 14.7
Amount of fluorine that was formed = 14.7 * 1 gm
                                                         = 14.7 gm
I hope that this answer has come to your help. 

false.

Explanation:

1) The increase of temperature is calcualte with the formula:

Q = M × C × ΔT.

2) In this case, you can write:

For water: Qw = Mw × Cw × ΔTw

For iron: Qi = Mi × Ci × ΔTi

3) Since the heat absorbed and the masses are equal, you get:

Qw = Qi ⇒ Cw×ΔTw = Ci×ΔTi, from where you can clear ΔTw

4) ΔTw = Ci×ΔTi / Cw

Replacing the values: ΔTw = 0.444 ΔTi / 4.18 ≈ 0.11 ΔTi.

5) Conclusion the temperature increase of water will be 0.11 times the increase of temperature of iron (this is smaller). So, the statement is false.