genyjoannerubiera
22.07.2019 •
Chemistry
The oxidation numbers of nitrogen in nh3, hno3, and no2 are, respectively: -3, -5, +4 +3, +5, +4 -3, +5, -4 -3, +5, +4
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Ответ:
x + (+1)3 = 0
x = -3
In HNO3 , let oxidation number of N be x
1 + x + (-2)3 = 0
x = +5
In NO2 , let oxidation number of N be x
x + (-2)2 = 0
x = +4
Ответ:
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