The partial pressure of ch4(g) is 0.175 atm and that of o2(g) is 0.250 atm in a mixture of the two gases. a. what is the mole fraction of each gas in the mixture? b. if the mixture occupies a volume of 10.5 l at 65c, calculate the total number of moles of gas in the mixture. c. calculate the number of grams of each gas in the mixture

As in the mixture? b. if the mixture occupies a volume of 10.5 l at 65c, calculate the total number of moles of gas in the mixture.c. calculate the number of grams of each gas in the mixtureask for details  follow  report  by  jatavionwpisd2272  5 days agoanswersleonelclara32  ·  ambitiousknow the answer?   add it here! leonelclara32rank:   ambitious330/5000/5my challenges

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The correct option is d.: 1.5 grams of glucose is produced from 2.20 g of CO₂.

To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

So, in this case, the balanced reaction is:

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:

CO₂: 6 moles H₂O: 6 moles C₆H₁₂O₆: 1 mole O₂: 6 moles

So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:

moles of CO₂= 0.05 moles

Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?

moles of C₆H₁₂O₆= 8.33*10⁻³

Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:

mass of glucose= 1.5 grams

In summary, the correct option is d.:  1.5 grams of glucose is produced from 2.20 g of CO₂.

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