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KitKat22Rose9
31.07.2019 •
Chemistry
The rate constant is found to be 3.9 x 10-5 m-1 s-1. calculate the rate of formation of ozone when the concentration of oxygen atoms is 3.0 x 10-14 molar and the concentration of diatomic oxygen is 1.3 x 10-14 molar.
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Ответ:
Determine the Chemical reaction:
O + O₂ → O₃
Note:
The Ozone is formed when an oxygen atom collides with a molecule of oxygen.
Given:
k = 3.9 x 10-5 M-1 s-1
Solution:
c(O) = 3.0 x 10⁻¹⁴ M
c(O₂) = 1.3 x 10⁻¹⁴ M
Required:
Find the rate of formation
rate of formation = k·c(O)·c(O₂)
rate of formation = (3.9 x 10⁻⁵ M⁻¹·s⁻¹) (1.3 x 10⁻¹⁴ M) (3.0 x 10⁻¹⁴ M)
rate of formation of ozone = 1.5 x 10⁻³² M/s
Ответ:
Explanation:
1) The ozone is formed when oxygen atoms (O) react with oxygen diatomic molecules (O₂)
2) The chemical equation for the formation of ozone is:
O + O₂ → O₃
3) The rate of the formation is:
rate = k[O][O2]
4) You are given the three values k ,[O] and [O2], so just plug in and calculate:
rate = 3.9·10⁻⁵ M⁻¹·s⁻¹ · 1.3·10⁻¹⁴ M · 3.0·10⁻¹⁴ M. = 1.5x10⁻³² M/s
Ответ:
Explanation:
Formula to calculate how many particles are left is as follows.
N =![N_{0} (\frac{1}{2})^{l}](/tpl/images/0175/5440/33dff.png)
where,
= number of initial particles
l = number of half lives
As it is given that number of initial particles is
and number of half-lives is 3.
Hence, putting the given values into the above equation as follows.
N =![N_{0} (\frac{1}{2})^{l}](/tpl/images/0175/5440/f9546.png)
=![128 \times 10^{10}(\frac{1}{2})^{3}](/tpl/images/0175/5440/82c77.png)
=![16 \times 10^{10}](/tpl/images/0175/5440/cfa08.png)
or,![1.6 \times 10^{11}](/tpl/images/0175/5440/171a7.png)
Thus, we can conclude that
particles of radioactive nuclei remain in the given sample.
In five hours we've gone through 5 half lives so the answer is:
particles