The reaction between potassium chlorate and red phosphorus takes place when you strike a match on a matchbox. If you were to react 37.1 g of potassium chlorate () with excess red phosphorus, what mass of tetraphosphorus decaoxide () could be produced
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Ответ:
25.55 grams of tetraphosphorus decaoxide could be produced by the reaction.
Explanation:
First the balanced chemical reaction of the production of tetraphosphorus decaoxide is to be known.
The chemical equation is
10 KClO3 + 3P4⇒ 3 P4010 + 10 KCl
The number of moles of KCLO3 will be calculated by the formula:
number of moles = mass of the compound given ÷ atomic mass of the compound
n = 37.1 ÷ 122.55 ( atomic mass of KClO3 is 122.55 gm/mole)
= 0.30 moles
From the stoichiometry
10 moles of KClO3 is required to produce 3 moles of P4O10
when 0.30 moles of KClO3 is used x moles of P4O10 is formed
thus, 3 ÷ 10 = x ÷ 0.30
= 0.09 moles of KClO3 is produced
To know the mass of P4O10 apply the formula
mass = number of moles × atomic mass
= 0.09 × 283.886 ( atomic mass of P4O10 is 283.88 gram/mole)
= 25.55 grams of P4O10 could be produced.
Ответ:
B I personally think..
Step-by-step explanation:
Hi,
Use Differential Formula :
d(u(x) • v(x))/dx = u'(x) • v(x) + u(x) • v'(x)
at x = 1 :
d(u(1) • v(1))/dx = u'(1) • v(1) + u(1) • v'(1)
d(u(1) • v(1))/dx = -5 • 6 + 4 • -2
d(u(1) • v(1))/dx = -30 - 8
d(u(1) • v(1))/dx = -38
Hope this helped :)