Chemistry: The solubility of a gas in water is 0.66 g/L at 15 kPa of pressure. What is the solubility when the pressure is increased to 40.0 kPa?

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The solubility of a gas in water is 0.66 g/L at 15

chrissy5189

28.01.2022

The correct answer to the following question will be "1.76 g/L".

Explanation:

The given values are:

P₁ = 15 kPa

Solubility of water, C₁ = 0.66 g/L

P₂ = 40.0 kPa

C₂ = ?

Now,

According to Henry's Law,

⇒ $\frac{P_{1}}{P_{2}}=\frac{C_{1}}{C_{2}}$

⇒ $C_{2}=\frac{C_{1}\times P_{2}}{P_{1}}$

On putting the estimated values, we get

⇒ $=\frac{0.66\times 40}{15}$

⇒ $=\frac{26.4}{15}$

⇒ $=1.76 \ g/L$

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