The sp of strontium carbonate, SrCO3, is 5.60×10−10 . Calculate the solubility of this compound in g/L.

3.50 × 10⁻³ g/L

Explanation:

Step 1: Make an ICE chart for the solution of SrCO₃

"S" represents the molar solubility.

         SrCO₃(s) ⇄ Sr²⁺(aq) + CO₃²⁻(aq)

I                             0               0

C                           +S              +S

E                             S               S

The solubility product constant (Ksp) is:

Ksp = [Sr²⁺] [CO₃²⁻] = S²

S = √Ksp = √5.60 × 10⁻¹⁰ = 2.37 × 10⁻⁵ M

Step 2: Convert "S" to g/L

The molar mass of SrCO₃ is 147.63 g/mol.

2.37 × 10⁻⁵ mol/L × 147.63 g/mol = 3.50 × 10⁻³ g/L

No

Explanation:

We first find the solubility of the copper sulphate salt

Number of moles= 4.6 moles

Volume =1.75 L

Molarity= number of moles/ volume = 4.6/1.75= 2.6 molL-1

Hence, only 2.6 moles of Copper II sulphate dissolves in 1.75L of water. Hence 4.6 moles of copper II Sulphate dies not dissolve in 1.75 L of water.