The standard heat of combustion is shown in the following

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bando187

10.04.2022

The given question is incomplete. The complete question is:

The standard heat of combustion is shown in the following chemical equation $C_9H_{20}(g)+14O_2(g)\rightarrow 9CO_2(g)+10H_2O$ $\Delta H_{rxn}=-6125.21kJ/mol$ . If 130 g of nonane combusts , how much heat is released?

6211.21 kJ

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of 1 mole of nonane = 6125.21 kJ

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

1 mole of nonane $(C_9H_{20})$ weighs = 128.2 g

Thus we can say:

128.2 g of nonane on combustion releases = 6125.21 kJ

Thus 130 g of $C_4H_{10}$ on combustion releases = $\frac{6125.21}{128.2}\times 130=6211.21kJ$

Thus the heat of combustion of 130 g of nonane is 6211.21 kJ

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The standard heat of combustion is shown in the following chemical equation CgH 20 (g) + 140 2(g) 9CO 2(g) + 10H 2 o (1) delta

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