The value of δg°\ for the conversion of dihydroxyacetone

Ответ:

mmaglaya1

30.12.2021

The concentration of glyceraldehyde-3-phosphate is 0.0886 nM.

Explanation:

The chemical equation for the conversion follows:

$\text{Dihydroxyacetone phosphate}\rightleftharpoons \text{Glyceraldehyde-3-phosphate}$

The expression for $K_{eq}$ of above equation is:

$K_{eq}=\frac{\text{[Glyceraldehyde-3-phosphate]}}{\text{[Dihydroxyacetone phosphate]}}$

Let the concentration of glyceraldehyde -3-phosphate be 'x'

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K_1$

where,

$\Delta G^o$ = standard Gibbs free energy = 7.53 kJ/mol = 7530 J/mol (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.3145J/K mol

T = temperature = 25^oC=[273+25]K=298K

[Glyceraldehyde-3-phosphate] = x

[Dihydroxyacetone phosphate] = 1.85 mM

Putting values in above equation, we get:

$7530J/mol=-(8.3145J/Kmol)\times 298K\times \ln (\frac{x}{1.85})\\\\x=0.0886mM$

Hence, the concentration of glyceraldehyde-3-phosphate is 0.0886 nM.

0,0(0 оценок)