The vapor pressure of a substance is measured over a range of temperatures. a plot of the natural log of the vapor pressure versus the inverse of the temperature (in kelvin) produces a straight line with a slope of −3.58×103k.what is the enthalpy of vaporization of the substance? 29.8 kj/mol2.32×1023kj/mol0.431 kj/mol294 kj/mol

ΔHvap = 431 J/mol

Explanation:

The relation between the vapor pressure and the absolute temperature is given by the Clausius-Clapeyron equation.

where,

p: vapor pressure

ΔHvap: enthalpy of vaporization

T: absolute temperature

C: constant

We can see that this corresponds to a linear equation with slope -ΔHvap/R and intercept C. If the slope is -3.58 × 10³ K,

-3.58 × 10³ K = -ΔHvap/R

3.58 × 10³ K = ΔHvap/(8.314 J/K.mol)

ΔHvap = 431 J/mol

I'll explain.

Explanation:

The molecules of two different elements, nitrogen and oxygen, make up about 99 percent of the air. The rest includes small amounts of argon and carbon dioxide. Oxygen is the life-giving element in the air. You can tell because they're on the periodic table which is a table for elements.