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gabriellestaleyga16
04.01.2020 •
Chemistry
The volume, in liters, of 835 g so3 at stp. show your work.
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Ответ:
233.856 L
Explanation:
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
So first of all you should know the amount of moles that represents 835 g of SO₃. For that, you know that:
S: 32 g/moleO: 16 g/molSo: SO₃= 32 g/mol + 3*16 g/mol= 80 g/mol
Now a rule of three applies as follows: if 80 g of SO₃ are contained in 1 mol, 835 g of the compound, how many moles are there?
moles= 10.44
Finally, you apply a new rule of three as follows: if, according to STP, 1 mole occupies a volume of 22.4 L, 10.44 moles, how much volume does it occupy?
volume=![\frac{10.44 moles*22.4 L}{1 mole}](/tpl/images/0442/2432/f5c49.png)
volume=233.856 L
The volume of 835 g SO₃ at STP is 233.856 L
Ответ:
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