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Elexis8591
23.03.2020 •
Chemistry
Use the electron-transfer method to balance this equation:
Zn(s) + HCl(aq) → ZnCl2(aq) + H2(g)
a. 2Zn(s) + HCl(aq) → ZnCl2(aq) + H2(g)
b. Zn(s) + 2HCl(aq) →ZnCl2(aq) + H2(g)
c. Zn(s) + HCl(aq) →ZnCl2(aq) + H2(g)
d. 2Zn(s) + 4HCl(aq) → 2ZnCl2(aq) + 2H2(g)
e. 3Zn(s) + 3HCl(aq) →3ZnCl2(aq) + 3H2(g)
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Ответ:
The answer to your question is the letter d.
Explanation:
Data
Zn + HCl ⇒ ZnCl₂ + H₂
- Calculate the Oxidation number of reactants and products
Zn⁰ + H⁺¹Cl⁻¹ ⇒ Zn⁺²Cl₂⁻¹ + H₂⁰
- Determine which elements changed their oxidation numbers
Zn⁰ ⇒ Zn⁺² Zn lost 2e⁻
2H⁺¹ ⇒ H₂⁰ H won 2 e⁻
-Interchange the electrons lost and won
2( Zn⁰ ⇒ Zn⁺²)
2(2H⁺¹ ⇒ H₂⁰)
-Simplify
2Zn⁰ ⇒ 2Zn⁺²
4H⁺¹ ⇒ 2H₂⁰
-Substitute the coefficient in the equation
2Zn + 4HCl ⇒ 2ZnCl₂ + 2H₂
Reactant Element Product
2 Zn 2
4 H 4
4 Cl 4
- Now the reaction is balanced
Ответ:
The answer is just 20