Use the given Nernst equation, reaction, and conditions to find the potential of this cell. 2Ag+(aq) + Zn(s) → 2Ag(s) + Zn2+(aq) E° = +1.56 volts T = -90°C [Ag+] = 1.0 molar [Zn2+] = 10.0 molar `E = E° - (2.303RT)/(nF)"log"Q` A. 1.26 volts B. 1.53 volts C. 1.54 volts D. 1.60 volts

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