Using the equations
H2 (g) + F2 (g) → 2 HF (9) AH° = -79.2 kJ/mol
C(s) + 2 F2 (g) CF, (g) AH° = 141.3 kJ/mol
Determine the enthalpy for the reaction
C(s) + 4 HF (g) - CF. (g) + 2 H2 (g).

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lilspike420

08.02.2021

Chemistry

it’s the bes

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Using the equationsH2 (g) + F2 (g) → 2 HF (9) AH° = -79.2 kJ/molC(s) + 2 F2 (g) CF, (g) AH° = 141.3 kJ/molDetermine the enthalpy for the reactionC(s) + 4 HF (g) - CF. (g) + 2 H2 (g).