Ackussinglake63
16.06.2020 •
Chemistry
Using the solubility of Ca(IO3)2 that you determined in 0.01M KIO3 as a solvent, calculate the value of Ksp using only concentrations, that is assuming that all activity coefficients are 1.0. You should report 3 significant figures.
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Ответ:
Explanation:
Dissociation of Ca(IO₃)₂ is as follows:
Ca(IO₃)₂ ⇄ Ca²⁺ + 2IO₃⁻
This implies that for every mole of Ca(IO₃)₂ that dissolves in water' 1 mole of Ca²⁺ is obtained and 2 moles of IO₃⁻ is obtained.
The solubility in mol/L when Ca(IO₃)₂ is added to KIO₃ = 0.00341
Concentration of Ca²⁺ will be = 0.00341 M ˣ 1 = 0.00341 M ( i.e equal to the solubility of Ca(IO₃)₂)
Concentration of IO₃⁻ will be = 0.00341 M ˣ 2 = 0.00682 M
IO₃⁻ is also obtained from the dissociation of KIO₃ in water. the IO₃⁻ obtained from this process is = 0.01 M
The total concentration of IO₃⁻ now = 0.00682 M + 0.01 M = 0.01682 M
The solubility product can be calculated by the formula:
Ответ:
A compressed spring
Explanation: