Chemistry: Water at 4.4°c is to flow through a horizontal, commercial steel pipe having a length of 305 m at the rate of 150 gal/min. if a head of water of 6.1 m is available to overcome the friction loss f, calculate the pipe diameter.

Water at 4.4°c is to flow through a horizontal, commercial

emmacox069

06.01.2022

d = 70.5 mm

Explanation:

given,

length of pipe = 305 m

discharge rate = 150 gal/min

pipe diameter = ?

1 gal/min = 6.30902 × 10⁻⁵ m³/s

150 gal/min = 150 × 6.30902 × 10⁻⁵ m³/s

= 9.46 × 10⁻³ m³/s

$h = \dfrac{flv^2}{2gd}$

Q = A V

$h = \dfrac{fl(\dfrac{Q}{A})^2}{2gd}$

$h = \dfrac{fl(\dfrac{Q}{\dfrac{\pi}{4}d^2})^2}{2gd}$

$h= \dfrac{8flQ^2}{\pi^2gd^5}$

f = 0.048 from moody chart using P/D = 0.00015

$\dfrac{1}{d^5}= \dfrac{6.1\times \pi^2\times 9.8}{8\times 0.048\times 305\times 0.00946^2}$

d = 70.5 mm

Diameter of the pipe is equal to 70.5 mm

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oscarsanchez1530

14.09.2021

With 6 we should multiply gross photosynthesis (as we were measuring gross photosynthesis for 10 min).

Explanation:

According to this question:-

Net photosynthesis- 3mm/20min- 1.5mm/10min

Cellular respiration- 1mm/15min- 0.66mm/10min

Gross photosynthesis = Net photosynthesis + Cellular respiration = 1.5+0.66 = 2.16 (mm/10min)

Rate of photosynthesis = (gross photosynthesis)6 = 2.16 *6 = 12.96 mm/hr

As we gage the photosynthesis rate in hr.

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