Chemistry: What are the ion concentrations in a 0.12 m solution of alcl3? a) 0.12 m al3+ ions and 0.040 m cl- ions b) none of the answers c) 0.36 m al3+ ions and 0.12 m cl- ions d) 0.12 m al3+ ions and 0.36 m cl- ions e) 0.040 m al3+ ions and 0.040 m cl- ions

What are the ion concentrations in a 0.12 m solution

Ответ:

Silkyruthie

11.01.2022

Chemistry

Explanation:

To answer this question, we will need to write the dissociation equation of aluminum trichloride.

AlCl3 ——-> Al3+ + 3Cl-

It can be seen that when aluminum chloride dissociates, it gives one mole of aluminum ion and three moles of the chloride ion.

From here we can see that the concentration of the aluminum chloride equals that of the aluminum ion while that of the chloride ion is thrice that of the aluminum chloride. This means we simply multiply 0.12M by 3 to get the molarity of the chloride ion while that of the aluminum ion remains the same

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Ответ:

murtaghliam1

08.02.2023

Chemistry

The amount of heat release to freeze 65.8 g liquid water is $\boxed{-{\text{21}}{\text{.98 kJ}}}$ .

Further explanation:

Latent heat

The heat released or absorbed during the process of conversion physical state of a substance without altering the temperature is known as the latent heat.

In other words, when the physical state changes from liquid phase to solid phase without altering the temperature then the amount of heat released in this process is known as the latent heat fusion.

The formula to calculate heat released from the latent heat of fusion is,

${\text{q}}={\text{m}}{{\text{H}}_{\text{f}}}$ …… (1)

Here,

q is heat released.

m is mass of substance.

${{\text{H}}_{\text{f}}}$ is latent heat of fusion.

The mass of given liquid water is 65.8 g.

The latent heat of fusion for freezing process of water is -334 J/g.

Substitute 65.8 g for m and -334 J/g for ${{\text{H}}_{\text{f}}}$ in equation (1) as follows:

$\begin{aligned}{\text{q}}&={\text{m}}{{\text{H}}_{\text{f}}}\\&=\left({65.8{\text{ g}}}\right)\left({-334{\text{ J/g}}}\right)\\&=-21977.2{\text{ J}}\\\end{aligned}$

Here negative sign shows that heat is released in the process.

The heat released to freeze 65.8 g liquid water is 21977.2 J.

The heat released in kilojoule is,

$\begin{aligned}{\text{q}}&=\left({-21977.2{\text{ J}}}\right)\left({\frac{{1{\text{ kJ}}}}{{1000{\text{ J}}}}}\right)\\&=-21.9772{\text{ kJ}}\\&\approx-{\text{21}}{\text{.98 kJ}}\\\end{aligned}$

Learn more:

1. The difference between heat and temperature.:

2. Determine the process by which water enters into atmosphere?:

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Thermodynamics

Keywords: Latent, Heat, fusion, Latent heat of fusion, temperature, ice, water, vapors, equilibrium, heat required, heat released melting, heat release, heat absorbed, 21.98 kJ.

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What are the ion concentrations in a 0.12 m solution of alcl3? a) 0.12 m al3+ ions and 0.040 m cl- ions b) none of the answers c) 0.36 m al3+ ions and 0.12 m cl- ions d) 0.12 m al3+ ions and 0.36 m cl- ions e) 0.040 m al3+ ions and 0.040 m cl- ions

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