jambunny26
29.09.2021 •
Chemistry
What forces are happening when a rabbit is jumping
Solved
Show answers
More tips
- F Food and Cooking How to Make Delicious Plov: Secrets and Recipes...
- S Sport How to Learn to Pull Up on Monkey Bars?...
- L Leisure and Entertainment Scrapbooking: What is it and Why is it Becoming More Popular?...
- C Computers and Internet Where did torrents.ru move to?...
- B Business and Finance Understanding Cash Flow: What It Is and How It Works...
- C Computers and Internet What Are Peers and Seeds in Torrenting?...
- H Health and Medicine 10 Simple Techniques on How to Boost Your Mood...
- G Goods and services How to Choose the Right High Chair for Your Baby?...
- S Style and Beauty Learn how to tie a keffiyeh on your head like a pro...
Answers on questions: Chemistry
- M Mathematics Evaluate 2 x minus y2x−y for the given replacement values. x equals 6x=6 and y equals negative 15...
- E English Adependent clause joins with an independent clause to make a a. complex sentence b. compound sentence c. simple sentence d. compound-complex sentence...
- H History Who was Augusta Gregory? How did she die?...
- M Mathematics Use the drop-down menus to complete each equation so the statement about its solution is true. No Solutions 3 + 9 + 4 + = _ + _ One Solution 3 + 9 + 4 + = _ + _ Infinitely Many...
Ответ:
gravity
Explanation:
Ответ:
gravity
Explanation:
Ответ:
The balanced equation for the reaction is:
2C6H10 + 17O2 ==> 12CO2 + 10H2O
So for every 2 moles of C6H10 consumed, we should get 12 moles of CO2. Or to simplify, for each mole of C6H10, we should get 6 moles of CO2. Now let's calculate the molar mass of C6H10 and CO2 and then determine how many moles of each we really have.
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass C6H10 = 6*12.0107 + 10*1.00794 = 82.1436 g/mol
Molar mass CO2 = 12.0107 + 2*15.999 = 44.0087 g/mol
Moles C6H10 = 8.88 g / 82.1436 g/mol = 0.10810337 mol
Moles CO2 = 18.9 g / 44.0087 g/mol = 0.429460538 mol
Since we had 0.10810337 moles of C6H10, we should have gotten
6*0.10810337 = 0.648620221 moles of CO2, but only got 0.429460538 moles. So let's divide the actual yield by the theoretical yield to get the percentage yield.
0.429460538 / 0.648620221 = 0.662114014 = 66.2%