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allimaycatp8qgaq
23.12.2019 •
Chemistry
What is δg′° for the reaction ( k ′ eq measured at 25 °c)? (b) if the concentration of fructose 6-phosphate is adjusted to 1.5 m and that of glucose 6-phosphate is adjusted to 0.50 m, what is δg? (c) why are δg′° and δg different?
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Ответ:
a.![-1.68 \frac{kJ}{mol}](/tpl/images/0430/8692/df64c.png)
b.![-4.40 \frac{kJ}{mol}](/tpl/images/0430/8692/72c48.png)
c. Standard conditions provide 1 M molarity for each component, while non-standard conditions provide specific concentrations
Explanation:
a. The original problem states that:
For an equilibrium:
This means:
Solving for the standard Gibbs free energy change:
b. Now we will solve for the non-standard Gibbs free energy change given by the equation:
Here:
We obtain:
c. The standard Gibbs free energy change is measured for 1 M concentration of each molarity, however, the non-standard Gibbs free energy change is measured for the given molarities of 1.5 M and 0.50 M. Due to different conditions, we obtain different values.
Ответ: