Chemistry: What is the change in energy of an atom if the wavelength of the photon absorbed by the atom is equal to 4.64 x 10-7 meters? (planck’s constant is 6.626 x 10-34 joule seconds; the speed of light is 2.998 x 108 m/s)?

Astereo isomer is a isomeric molecule that has the same molecular formula formula and sequence in different structural forms, the stereoisomers in the above complex are ni, nh3 and br...

What is the change in energy of an atom if the

Ответ:

abdullahs4639

12.03.2022

Chemistry

Hello!

We have the following data:

v (speed of light) = $2.998*10^8\:m/s$

λ (wavelength) = $4.64*10^{-7}\:m$

First, let's find the frequency of the wave, let's see:

$f = \dfrac{v}{\lambda}$

$f = \dfrac{2.998*10^8\:\diagup\!\!\!\!\!m/s}{4.64*10^{-7}\:\diagup\!\!\!\!\!m}$

$f \approx 0.6461*10^{8-(-7)}$

$f \approx 0.6461*10^{8+7}$

$f \approx 0.6461*10^{15}$

$\boxed{f \approx 6.461*10^{14}\:Hz}$

Now, find the Energy of the Photon by Planck's Equation, given:

E (photon energy) =? (in Joule)

h (Planck's constant) = $6.626*10^{-34}\:J * s$

f (radiation frequency) = $6.461*10^{14}\:Hz$

Therefore, we have:

E = h*f

$E = 6.626*10^{-34}*6.461*10^{14}$

$E \approx 42.81*10^{-34+14}$

$E \approx 42.81*10^{-20}$

$\boxed{\boxed{E \approx 4.281*10^{-19}\:Joule}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

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What is the change in energy of an atom if the wavelength of the photon absorbed by the atom is equal to 4.64 x 10-7 meters? (planck’s constant is 6.626 x 10-34 joule seconds; the speed of light is 2.998 x 108 m/s)?

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