What is the effect of adding more co2 to the following equilibrium reaction? co2 + h2o h2co3

a. more h2co3 is produced.
b. more h2o is produced.
c. the equilibrium is pushed in the direction of reactants.
d. no change

also,

which of the following is the correct expression for the rate of the following reaction? note: all species are gaseous.2so3 < --> 2so2 + o2a. [so3]2 / ([so2]2 x [o2])
b. [so2]2 x [o2] / [so3]
c. [so2]2 x [o2] / [so3]2
d. [so2] x [o2] / [so3]

1) A. More H2CO3 is produced.

2) C.

Explanation:1) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

If concentration of is increased, that is the reactant is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of takes place. Therefore, the equilibrium will shift in the right direction, i.e. will be formed.

2) The rate of a equilibrium reaction is determined by equilibrium constant. Equilibrium constant is the ratio of the product of the concentration of products to the product of the concentration of reactants each term raised to their stochiometric coefficients.

The intermolecular bonding in the solid is van der Waals dispersion forces. That means that it will have a lower melting point than diamond or graphite where you have giant covalent bonding. In fact C60 sublimes at 800 K (527°C). Diamond and graphite sublime at around 4000 K.

Explanation: