What is the element for trifluoroborane
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Ответ:
Ответ:
Total moles of HNO3 = 50 ml x 0.20 m = 0.01 mol
NH3 + H+ = NH4+, moles of NH4+ = 0.01 M x l
H3O+ = NH3 = N
Total volume of both compounds = 50 ml + 50 ml = 100 ml = 0.1 l
For ammonium ion NH4+ = 0.01 M x l / 0.1 l = 0.1 M
Kw = 1.0 x 10^-14; Kb = 1.8 x 10^-5; Ka = Kw/Kb = 1.0 x 10^-14 / 1.8 x 10^-5
Ka = 5.55 x 10^-10 = [H3O+ + 1][NH3] / [NH4^+1] = N x N / (0.1 - N)
Since the value of the N is very less and almost negligible 5.55 x 10^-10 = N^2/0.1
N^2 = 55.5 x 10^-12 => N = 7.44 x 10^-6 => H3O+ = 7.44 x 10^-6 Hence the pH value is 5.13