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jessec27019
14.05.2021 •
Chemistry
What is the final concentration of Ca(OH)2
when 255 mL of 0.250 M Ca(OH)2 is mixed
with 55.0 mL of 0.65 M Ca(OH)2?
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Ответ:
20 drops of ethanol dispensed by dropper will be 1.0 mL ethanol.
Explanation:
Mass of 15 drops of ethanol = 0.60 g
Mass of 1 drop of an ethanol =![\frac{0.60 g}{15}=0.04 g](/tpl/images/0405/9369/f238f.png)
Mass of 1.0 mL of ethanol = m
Volume of ethanol = 1.0 mL
Density of an ethanol = d = 0.80 g/ml
Number of drops in 0.80 g of ethanol = x
20 drops of ethanol dispensed by dropper will be 1.0 mL ethanol.