What is the formula for diboron hexabromide

             First of all we will calculate the amount of CO₂ produced by burning 10 grams of Methane. The balance chemical equation is as follow:

                                CH₄  +  2 O₂   →    CO₂  +  2 H₂O

First we will calculate the moles of CH₄ as,

                            Moles  =  Mass / M.Mass

                            Moles  =  10 g / 16 g/mol

                            Moles  =  0.625 moles

Secondly calculate the moles of CO₂ produces theoretically,

According to equation,

                             1 mole of CH₄ produces  =  1 mole of CO₂

So,

               0.625 moles of CH₄ will produce  = X moles of CO₂

Solving for X,

                      X  =  1 mole × 0.625 moles / 1 mole

                     X =  0.625 moles of CO₂

At last calculate mass of CO₂ as,

                     Mass  =  Moles × M.Mass

                     Mass  =  0.625 mole × 44 g/mol

                     Mass  =  27.5 g ≈ 27 g

Conclusion:

                    From above calculation it can be concluded that this reaction is following law of conservation of mass. There is neither a gain nor a loss of mass during the reaction. Also, this can be made possible when the given amount of methane is provided with excess of O₂ gas so that the methane is completely combusted.