Chemistry: What is the freezing point of a 0.82 m aqueous solution of a non-volatile non-electrolyte? PLEASE HELP

What is the freezing point of a 0.82 m aqueous solution

Ответ:

smarcalli6457

26.01.2022

-1.5 °C

Explanation:

The freezing-point depression is a colligative property, that is, the property of a solution. The freezing point of a solution is lower than the freezing point of the pure solvent. We can find the freezing-point depression of a solution of a non-volatile non-electrolyte solute using the following expression.

$\Delta T_f = K_f \times b$

where,

$\Delta T_f$ : the freezing-point depression K_f

: cryoscopic constant (For water, Kf = 1.86 °C/m)

: molality

$\Delta T_f = \frac{1.86\°C}{m} \times 0.82m = 1.5\°C$

The freezing-point of pure water is 0°C. The freezing-point of the solution is:

$0\°C-1.5\°C = -1.5\°C$

0,0(0 оценок)

Ответ:

kay4451

30.10.2022

Chemistry

Explanation: the salt water is homogenous mixture since the salt is being evenly distributed throughout the water. Salt is a solute and water is a solvent

0,0(0 оценок)

What is the freezing point of a 0.82 m aqueous solution of a non-volatile non-electrolyte?

PLEASE HELP

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Chemistry

Ask an AI advisor a question