What is the length (in cm) of the side of an iron ingot (rectangular box) that has a mass of 4.578 kg and has width = height = 5.00 cm
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Answer : The length of the side of an iron ingot (rectangular box) is 0.0233 cm.

Explanation : Given,

Width of rectangular box = 5.00 cm

Height of rectangular box = 5.00 cm

Mass of rectangular box = 4.578 g

Density of iron =

First we have to determine the volume of rectangular box.

Formula used :

Now we have to determine the length of rectangular box.

Formula for volume of rectangle :

where,

V = volume of rectangular box

l = length of rectangular box

b = width of rectangular box

h = height of rectangular box

Now put all the given values in the above formula, we get:

Therefore, the length of the side of an iron ingot (rectangular box) is 0.0233 cm.

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