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Savageboyn
21.07.2019 •
Chemistry
What is the mass occupied by 44.8 l of nitrogen (n2) at standard conditions?
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Ответ:
Volume = V = 44.8 L
Standard Pressure = P = 1 atm
Standard Temperature = T = 273 K
According to Ideal Gas Equation,
P V = n R T
Solving for n,
n = P V / R T
Putting values,
n = (1 atm × 44.8 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 273 K)
n = 1.99 mol
Now, calculating for mass,
n = Mass / M.mass
Or,
Mass = n × M.mass
Mass = 1.99 mol × 28 g.mol⁻¹
Mass = 55.72 grams
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