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angoliabirtio
08.11.2019 •
Chemistry
What is the molar mass of 81.50 g of gas exerting a pressure of 1.75 atm on the walls of a pressure or 1.27 atm on the walls of 4.92 l container of 307 k?
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Ответ:
PV = nRT
We may substitute the number of moles, n, with:
moles = mass / molecular mass
PV = mRT/Mr
Mr = (mRT)/PV
Substituting the values:
Mr = (81.5 * 0.082 * 307) / (1.75 * 4.92)
Mr = 238.3
The molar mass of the gas is 238.3 grams per mole.
Ответ: