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squawk1738
10.04.2020 •
Chemistry
What is the molar solubility of calcium carbonate ( CaCO3 ) in water? The solubility-product constant for CaCO3 is 4.5 × 10-9 at 25 °C.
A) 8.35
B) 9.5 × 10-5
C) 9.0 × 10-9
D) 2.3 × 10-9
E) 6.7 × 10-5
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Ответ:
Option E)
Explanation:
1. Write the solubility equation:
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻2. Write the concentrations below the equation:
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻A - s s s
3. Write the Ksp equation:
Ksp = [Ca²⁺] . [CO₃²⁻] ↔ the solid substances do not appearKsp = s × s4.5 × 10⁻⁹ = s²4. Solve the equation:
Ответ:
A
Explanation: