Alexandra079
22.04.2020 •
Chemistry
What is the molar solubility of zinc oxalate ( ZnC204) in water? The solubility-
product constant for ZnC04 is 2.7 x 10-8 at 25°C.
O
1.4 x 10-8
O 7.57
5.4 x 10-8
1.6 x 10-4
2.3 x 10-4
Question 12.11 noint)
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Ответ:
S = 1.6 E-4 M
Explanation:
ZnCO4 ↔ Zn2+ + CO42-S S S
∴ Ksp = 2.7 E-8 = [Zn2+]*[CO42-]
⇒ Ksp = (S)*(S) = S² = 2.7 E-8
⇒ S² = 2.7 E-8
⇒ S = √2.7 E-8
⇒ S = 1.6432 E-4 M ≅ 1.6 E-4 M
Ответ:
Explanation:
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