What is the percent dissociation of a 0.015m solution of hydrofluoric acid given the ka of hf is 6.3x10-4?
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Ответ:
HF + H2O ⇄ H3O(+) + F(-)
0.15 M - x x + x
2) Ka = [x]^2 / [0.15 - x]
3) Solution:
6.3x10^-4 = [x^2] / (0.15 - x)
=> x^2 = (0.15 - x) * 6.3 * 10^ -4
x^2 = 0.0000945 - 0.00063x
x^2 + 0.00063x - 0.0000945 = 0
Use the quadratic formula to find the solution: x = 0.00941
4) percent dissociation:
% = [0.00941 M / 0.15 M] * 100 = 6.27%
6.27%
Ответ: