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purplefive85
19.03.2020 •
Chemistry
What is the pressure in millimeters of mercury of 0.0130 molmol of helium gas with a volume of 210. mLmL at 55 ∘C∘C? (Hint: You must convert each quantity into the correct units (LL, atmatm, molmol, and KK) before substituting into the ideal gas law.)
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Ответ:
Answer : The pressure of the helium gas is, 1269.2 mmHg
Explanation :
To calculate the pressure of the gas we are using ideal gas equation:
where,
P = Pressure of
gas = ?
V = Volume of
gas = 210. mL = 0.210 L (1 L = 1000 mL)
n = number of moles
= 0.0130 mole
R = Gas constant =![0.0821L.atm/mol.K](/tpl/images/0554/5526/a454c.png)
T = Temperature of
gas = ![55^oC=273+55=328K](/tpl/images/0554/5526/577e4.png)
Putting values in above equation, we get:
Conversion used : (1 atm = 760 mmHg)
Thus, the pressure of the helium gas is, 1269.2 mmHg
Ответ: