What is the root mean square of co2 at 27oc
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Ответ:
The answer options provided are incorrect. The correct answer is 0.009g
Explanation:
Using PV = nRT
Where;
P = pressure (atm)
V = volume (L)
R = gas constant (0.0821 Latm/Kmol)
T = temperature (K)
n = number of moles
Based in the information provided;
V = 107mL = 107/1000 = 0.107L
P = 104.8kPa = 104800 Pa = 1.03atm
T = 30°C + 273.15 = 303.15K
PV = nRT
1.03 × 0.107 = n × 0.0821 × 303.15
0.1102 = 24.89n
n = 0.1102/24.89
n = 0.0044 mol
mole = mass/molar mass
Molar mass of H2 = 2g/mol
mass = molar mass × mole
mass = 2 × 0.0044
mass = 0.0088
mass = 0.009g