What is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15°C

0.33 cal⋅g-1°C-1  

Explanation:

The amount of heat required is determined from the formula:

q= mcΔT

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Explanation:

-12.4x + 8x > -0.4x - 5.2 - 2.7

Add similar elements: -12.4x + 8x = -4.4x

-4.4x > -0.4x - 5.2 - 2.7

Subtract -5.2 - 2.7: -7.9

-4.4x > -0.4x - 7.9

Multiply both sides by 10

-4.4x · 10 > -0.4x - 7.9 · 10

Refine

-44x > -4x - 79

Add 4x to both sides

-44x + 4x > -4x - 79 + 4x

Simplify

-40x > -79

Multiply both sides by -1 (Reverse the inequality)

-40x (-1) > -79 (-1)

Simplify

40x < 79

Divide both sides by 40

40x / 40 < 79 / 40

Simplify

x < ⁷⁹⁄₄₀

Turn the fraction into a decimal