What is the volume of 14.0 g of nitrogen gas, n2, at a pressure of 2.00 atm and temperature of 27.0 degree celsius
a. 5.60l
b. 6.15l
c. 11.2l
d. 12.3l

P = 2.00 atm = 2026.50hPa
T = 27°C = 300K
m = 14.0g              |
Mr = 28g/mol         |      n = m/M = 14g/28g/mol = 0,5mol
R = 83.1 [hPa*L]/[mol*K]

pV = nRT

        nRT        0,5mol * 83.1[hPa*L]/[mol*K] * 300K
V = = = 6.15L
           p                           2026.5hPa

Answer B.

Because they have an equal number of protons ad electrons