What is the volume of 23g of neon gas at 1C and a pressure of 2 atm

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Ответ:

husk84

13.03.2020

Chemistry

Given:

The probability of landing A is 0.70.

The probability of landing B is 0.60.

The probability of landing both is 0.50.

To find:

The probability of landing A given it lands B.

Solution:

We have,

P(A) = 0.70

P(B) = 0.60

$P(A\cap B) = 0.50$

The probability of landing A given it lands B is

$P\left(\dfrac{A}{B}\right)=\dfrac{P(A\cap B)}{P(B)}$

$P\left(\dfrac{A}{B}\right)=\dfrac{0.50}{0.60}$

$P\left(\dfrac{A}{B}\right)=\dfrac{5}{6}$

$P\left(\dfrac{A}{B}\right)=0.8333...$

$P\left(\dfrac{A}{B}\right)\approx 0.83$

Therefore, the probability of landing A given it lands B is about 0.83.

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What is the volume of 23g of neon gas at 1C and a pressure of 2 atm​