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karaisabelhill
30.06.2019 •
Chemistry
What mass of hcl, in grams, is required to react with 0.610 g of al(oh)3 ?
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Ответ:
0.8541 grams of HCl will be required.
Explanation: Moles can be calculated by using the formula:
Given mass of
= 0.610 g
Molar mass of
= 78 g/mol
Number of moles of
= 0.0078 moles
The reaction between
and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.
Chemical equation for the above reaction follows:
By Stoichiometry,
1 mole of
reacts with 3 moles of HCl
So, 0.0078 moles of
will react with
= 0.0234 moles
Mass of HCl is calculated by using the mole formula, we get
Molar mass of HCl = 36.5 g/mol
Putting values in the equation, we get
Mass of HCl required will be = 0.8541 grams
Ответ:
sir what im not understanding
Explanation: