What mass of LP (liquid propane) gas is required to heat 1.5 L of water from room temperature (25 °C) to boiling (100 °C)? Assume that during heating 85% of the heat emitted by the LP gas combustion goes to heating the water and the rest is lost to the surroundings. Note that LP has a heat of combustion of -2044 kJ/mol
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Ответ:
Substance B
Explanation:
Molar heat of A = 31.2J/mole.°C
Molar heat of B = 11.2 J/mole∙°C.
The molar heat of a substance is the amount of heat that must be added to a mole of a substance to raise the temperature by 1°C.
Substance B will heat up faster compared to A. It has a smaller molar heat compared to A. This suggests that it will require lesser heat to raise its temperature by 1°C.