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hannahkharel2
24.11.2020 •
Chemistry
What volume is occupied by 3.00 moles of nitrogen under a pressure of 202 kPa and a temperature of 323K? R = 8.314 kPa L/mol K INICI
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Ответ:
39.9 L
Explanation:
Use PV = nRT to solve this problem.
Substitute the values known.
P is pressure, which is 202 kPa, V is volume, which we do not know, n is moles, which is 3, R is 8.314, and T is temperature, which is 323K.
Set up your equation as follows![202 kPa V = 3.00mol (\frac{8.314 kPa L }{mol K} ) 323K](/tpl/images/0926/0597/a5628.png)
Solve for V, multiply the right side of the equation and divide by the pressure, 202 kPa.
This results in Volume being 39.9 L
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