What volume of 6.00 m naoh would be required to increase the ph to 4.93?

The Volume of  NaOH is mathematically given as

V=3.2 L

Volume of  NaOH

Generally the formula for PH is

Ph= Pka + log[A^-]/[HA]

4.93 = 4.76 + log((40+X)/(60-X))

0.17 = log ((40+X)/(60-X))

Therefore

X= 19.66 mmol = 0.019 mol

Generally the formula for molarity is

M= number of moles / volume    

6 = 0.019 / V

V=3.2 L

For more information on Chemical Reaction

link

According to this formula:
PH= Pka + ㏒[A^-]/[HA]
when we have the value of PH=4.93 & Pka (missing in your question) = 4.76 &
no.of mole of acetate = 40 mmol & no.of mole of acetic acid= 60
so by substitution:
4.93 = 4.76 + ㏒((40+X)/(60-X))
0.17 = ㏒ ((40+X)/(60-X))
∴X= 19.66 mmol = 0.019 mol
finally we can get the volume from this formula of the molarity:
molarity = number of moles / volume 
      6      = 0.019 / V
∴V= 0.0032 mL = 3.2 L

Explanation:

Hello.

In this case, since chromium (III) oxide and solid carbon are respectively Cr₂O₃ and C, the corresponding chemical reaction to yield solid chromium and oxygen is:

However, since two chromium atoms are present at the reactants yet one at the products and three oxygen atoms at the reactants and two at the products, we need to balance it as follows:

Best regards!