Chemistry: What would be the temperature change 3.0 g of water absorbed 15 j of heat

What would be the temperature change 3.0 g of

Ответ:

iwannasleep

10.03.2022

Chemistry

1.2 °C

Step-by-step explanation:

The formula relating the heat (q) absorbed by an object, the mass (m), and the temperature change (ΔT) is

q = mCΔT Divide both sides by mC

ΔT = q/(mC)

Data:

q = 15 J

m = 3.0 g

C = 4.184 J·°C⁻¹g⁻¹

Calculation:

ΔT = 15/(3.0 × 4.184)

ΔT = 15/12.6

ΔT = 1.2 °C

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Ответ:

lizzieee51

10.03.2022

Chemistry

The change in temperature of the sample has been $\rm 1.2\;^\circ C$ .

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The expression for specific heat has been given as:

$q=mc\Delta T$

Computation for Change in Temperature

For the given water sample,

The mass of sample has been $m=3\;\rm g$

The heat absorbed by the sample has been $q=15\;\rm J$

The specific heat of water has been $c=4.184 \;\rm J./^\circ C.g$

Substituting the values for change in temperature, $\Delta T$ :

$15=3\;\times\;4.184 \;\times\;\Delta T\\\Delta T=\dfrac{15}{3\;\times\;4.184 } \\\Delta T=1.2\;^\circ \rm C$

The change in temperature of the sample has been $\rm 1.2\;^\circ C$ .

Learn more about specific heat here:

link

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Ответ:

RKennedy3654

03.04.2023

Chemistry

Explanation:

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What would be the temperature change 3.0 g of water absorbed 15 j of heat

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