When an electron of a hydrogen atom travels from n=4 to n=2, a photon of energy 4.165•10^-19 joules is released. calculate the wavelength associated with this radiation.
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Ответ:
Energy level diagrams and the hydrogen atom ... Consider the photon emitted when an electron drops from the n=4 to the n=2 state to the photon emitted
Ответ:
Energy of photon, E = hν
Frequency of photon,
Thus, energy of photon,
Therefore, 4.165 × 10-19 joules =
λ = 4.77 × 10-7 meters
The frequency of a photon having energy of 4.165 × 10-34 joules is 4.77 × 10-7 meters.
Explanation:
Plato
Ответ:
2Al + Fe2O3 ——-> Al2O3 + 2Fe
This is a single displacement reaction