warrior4516
04.05.2021 •
Chemistry
When the volume of a gas is changed from 3.6l to 15.5l the temperature will change from c to 87c
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Ответ:
Food Value = CcalΔT/m
So, the food value for the snackbar would be
Food value = (6.15 kJ/°C)(1.37°C)/0.721 g = 11.68 kJ/g
Convert kJ to cal (1 kJ = 239 cal)
Food value = 11.68*239 = 2791.52 cal/g