Where does the process of solar energy formation begins? a. sun’s photosphere zone b. sun’s convective zone c. sun’s radioactive zone d. sun’s core e. sun’s corona

Option D is correct.

Explanation:

The formation of solar energy begins from the core of sun.

Sun is made up of gases, mainly hydrogen and helium.

The temperature of the core of sun is much higher than the corona. So, inside the core of sun, the fusion reaction of hydrogen takes place and emits a tremendous amount of energy in form of heat, light and other forms of energy. This is called solar energy.

Technically known as nuclear fusion, this process releases an incredible amount of energy in the form of light and heat.

Sun’s core

i) No electron is emitted. Hence, no kinetic energy or velocity of emitted electron

ii) KE = 6.85 x 10⁻¹⁹ J; v = 1.23 x 10⁶ m/s

Explanation:

Using the formula: Kinetic energy, KE = hc/λ - E₀

where h = the Plank constant 6.63 x 10⁻³⁴ J s,

c is velocity of light = 3.00 x 10⁸ m/s

λ = wavelength of incident light in nm

E₀ = work function in Joules

Note: 1 eV = 1.602×10⁻¹⁹ Joules

Also, using KE = 1/2 mv²

v = √(2KE/m)

where m is mass of electron = 9.11 x 10⁻³¹ Kg

i) KE = hc/λ - E₀

KE = (6.63 x 10⁻³⁴ Js x 3.00 x 10⁸ m/s) / 650 x 10⁻⁹ m - (2.09 x 1.602×10⁻¹⁹ J)

KE = 3.06 x 10⁻¹⁹ J - 3.35 x 10⁻¹⁹  = - 2.9 x 10⁻²⁰ J

Since KE is negative, no electron is emitted. Thus, there is no kinetic energy or velocity of electron.

ii) KE = hc/λ - E₀

KE = (6.63 x 10⁻³⁴ Js x 3.00 x 10⁸ m/s) / 195 x 10⁻⁹ m - (2.09 x 1.602×10⁻¹⁹ J)

KE = 10.2 x 10⁻¹⁹ J - 3.35 x 10⁻¹⁹

KE = 6.85 x 10⁻¹⁹ J

Velocity, v = √(2KE/m)

v = √( 2 x 6.85 x 10⁻¹⁹ J / 9.11 x 10⁻³¹ Kg)

v = 1.23 x 10⁶ m/s