Chemistry: Which of the following is the correct electron configuration for titanium (ti)?

Which of the following is the correct electron

Ответ:

dayanara72

11.04.2023

Explanation:

According to ideal gas equation, the product of pressure and volume equals to the product of number of moles, gas constant and temperature.

Mathematically, PV = nRT

Since, it is given that pressure is constant and Charle's law states that at constant pressure volume of an ideal gas is directly proportional to the absolute temperature.

Therefore, $V \propto T$

$\frac{V}{T}$ = constant

So, number of moles will also be constant then. Hence, the formula will be as follows.

$\frac{V_{1}}{T_{1}}$ = $\frac{V_{2}}{T_{2}}$

As it is given that $V_{1}$ is 9.53 L, $V_{2}$ is 4.36 L, $T_{1}$ is $215^{o}C$ that is also equal to (215 + 273) K = 488 K.

Now, putting these values into the formula as follows.

$\frac{V_{1}}{T_{1}}$ = $\frac{V_{2}}{T_{2}}$

$\frac{9.53 L}{488 K}$ = $\frac{4.36 L}{T_{2}}$

$T_{2}$ = 223.26 K

Temperature in degree celsius will be (223.26 K - 273 K) = $-49.73^{o}C$

Thus, we can conclude that temperature (in °C) is needed to reduce the volume to 4.36 L is $-49.73^{o}C$ .

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Which of the following is the correct electron configuration for titanium (ti)?

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