Which of the following statements about photosynthesis is correct? (multiple answers may be correct) A: Carbon dioxide serves as final acceptor of high energy electrons provided by the light reactions B: Water serves only as an electron donor in oxygenic photosynthesis C: The oxygen released by oxygenic photosynthesis originates from water D: Hydrogen sulfide can also serve as electron donor in oxygenic photosynthesis E: in anoxygenic photosynthesis carbon dioxide does not serve as final electron acceptor.

The correct statements are:

B: Water serves only as an electron donor in oxygenic photosyntheisis

C: The oxygen released by oxygenic photosynthesis originates from water

E: in anoxygenic photosynthesis, carbon dioxide does not serve as final electron acceptor.

Explanation:

In oxygenic photosynthesis, the final high energy electron acceptor is NADP, hence statement 'A' is false. In oxygenic photosynthesis, water is split to generate electrons to reduce P680 back to its resting state, thus releasing oxygen in the process.Hence statement 'B' is true.Statement 'C' is also true, as oxygen is released when water molecule is split.Hydrogen sulfide generally serves as an good electron donor in anoxygenic photosynthesis. Hence, statement 'D' is false.unlike in oxygenic photosynthesis, where NADP is the final electron acceptor, no NADP is available in anoxygenic photosynthesis and electrons are cycled back into the system. Hence statement 'E' is true

The given question is incomplete. The complete question is as follows.

On the basis of periodic trends, choose the larger atom from each pair (if possible): match the elements in the left column to the appropriate blanks in the sentences on the right. make certain each sentence is complete before submitting your answer.

          Sn, F, Ge, not predictable, Cr

Of Ge or Po, the larger atom is

Of F or Se, the larger atom is

Of Sn or I, the larger atom is

Of Cr or W, the larger atom is

Explanation:

When we move down a group then there occurs an increase in atomic size of the atoms due to increase in the number of electrons.

Ge is a group 14 element which lies in period 4 and Po is a group 16 element that lies in period 6. As polonium is larger in size as compared to germanium.

Fluorine is a group 17 element and lies in period 2. Selenium is a group 16 element lies in 4. Therefore, selenium is larger in size as compared to fluorine.

Sn is a group 14 element that lies in period 5 and I is a group 17 element that lies in period 5. Hence, I is a larger atom.

Cr is a d-block element which lies in period 4 and W is also a d-block element which lies in period 6. Hence, W is larger in size than Cr.

Thus, we can conclude that given blanks are matched as follows.

Of Ge or Po, the larger atom is Po.Of F or Se, the larger atom is Se.Of Sn or I, the larger atom is I.Of Cr or W, the larger atom is W.