Which of the following would require more energy to heat it from 10 degrees Celsius to 20 degrees Celsius? a. 200kg of water b. 200kg of aluminum c. 100kg of steel

A. 2.65 atm.

B. 18.11 g/L.

Explanation:

A. Determination of the pressure

Mass of N₂O = 21.3 g

Volume = 5.76 L

Temperature (T) = 111 °C

Pressure (P) =.?

First, we shall determine the number of mole in 21.3 g of dinitrogen monoxide, N₂O. This can be obtained as follow:

Mass of N₂O = 21.3 g

Molar mass of N₂O = (14×2) + 16

= 28 + 16

= 44 g/mol

Mole of N₂O =?

Mole = mass /Molar mass

Mole of N₂O = 21.3/44

Mole of N₂O = 0.484 mole

Next, we shall convert 111°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 111 °C

Temperature (T) = 111 °C + 273

Temperature (T) = 384 K

Finally, we shall determine the pressure. This can be obtained as follow:

Number mole of N₂O = 0.484 mole

Volume = 5.76 L

Temperature (T) = 384 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =.?

PV = nRT

P × 5.76 = 0.484 × 0.0821 × 384

Divide both side by 5.76

P = (0.484 × 0.0821 × 384) / 5.76

P = 2.65 atm

B. Determination of the density of CFCl₃

Temperature (T) = 157°C

Pressure (P) = 4.65 atm.

Density of CFCl₃ =?

First, we shall determine the molar mass of CFCl₃. This can be obtained as follow:

Molar mass of CFCl₃ = 12 + 19 + (35.5×3)

= 12 + 19 + 106.5

= 137.5 g/mol

Next, we shall convert 157°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 157 °C

Temperature (T) = 157 °C + 273

Temperature (T) = 430 K

Finally, we shall determine the density of CFCl₃. This can be obtained as follow:

Temperature (T) = 430 K

Pressure (P) = 4.65 atm.

Molar mass of CFCl₃ (M) = 137.5 g/mol

Gas constant (R) = 0.0821 atm.L/Kmol

Density (D) of CFCl₃ =?

D = PM / RT

D = (4.65 × 137.5) / (0.0821 × 430)

D = 18.11 g/L